Wednesday, 29 January 2014

January combinations - Solutions

Usually this rubric draws the most comments.
This time one of the regular readers answered on all five combinations, even if in one example he proposed the solution which was not my choice during the game.
You can see his answers if you follows the link January combinations .
I will complete his thoughts and analysis by my comments and the names of the players from the games.
Enjoy the solutions!

Bejtovic Jasmin 2353 - Thorgeirsson Sverir 2120
Scandinavian Open, Copenhagen 2008

1.e7 Re8 (...Rf7 2.Be6) 2.Be6+ 

(In the game I actually played 2. Qh4, g6 3. Qxf6, gxf5 4. Ng5 and won easy Jasmin Bejtovic)

Kh8 3.Nh4 (w/ idea Ng6+ and Qh4#).

If black tries 3...Ne5 we play 4.Rxe5, renewing the threat, and now 
4...Qxe5 fails to 5.Qxe5 fxe5 6.Rf3, and mate next move. 

(I would add here that Tom probably forgot to write 6. Ng6+, hxg6 7. Rf3 with mate next move Jasmin Bejtovic)
Black can play 3...h6, then I guess 4.Ng6+ Kh7 5.Qd3 w/idea Nf8++. 

Bejtovic Jasmin 2402 - Semcesen Daniel 2488
Rilton Cup, Stockholm 2013

Maybe the best try is 1.d5, w/ the idea Rd4. It counters Black's tactical idea of pushing the c-pawn. 1...c6 2.Rd4 and if 2...cxd5 3.Rb5. 

This is indeed the best continuation and after moves that Tom gave as the solution, Daniel and I agreed on draw.
Any other continuation (including Rxc7, Rc4) gives Black the possibility to play on.

Formento Paolo 2175 - Bejtovic Jasmin 2394
Crespi Memorial, Milan 2013

Qd1# would be good for black, so 1...Rxh2 and White cannot take. If 2.Ne2

(Tom meant  2.Nf2 Jasmin Bejtovic)

 Qd1+ anyway, 2...Nxd1 3.Rh1+ Ng1 4.Rxg1#

Mitchell Robert 2125 - Bejtovic Jasmin 2385
119th Scottish Championship, Glasgow 2012

The idea is probably to make ...Bxe4 and...Ng3+ work, but 1...h6 2.Qf6+ Kg8 3.Rd1 looks good for White... So 1...Bxe4 2.Rxe4 h6 (2.fxe4 h6 and the queen has to move, allowing ...Ng3+ or the fork ...Ne3) and now if 3.Rxd4? hxg5 there's a double threat (taking on d4 and Ng3+!) and if 4.Rg4 there is ...Ne3. So 3.Qg4. Mmm. 3...Ne3? 4.Rxd4 cxd4 5.Qe7+-... ok, doesn't work. 
1...Bxe4 2.Rxe4 f6. After 3.Qg4 i have h5 the queen is trapped... but now White has the resource Rd7+, so 4.Rxd4 hxg5 5.Rd7+ +-. Actually Black has 3.Rxd4 fxg5 4.Rd7+ +-.

Ok, so now the idea is to trap the queen : 
2.Rxe4 h6
3.Qg4 Qd3 (hitting f1 / threatening ...Ne3) 
4.Rfe1? h5! -+ 

I have to admit that I got confused here.
The most of the lines are accurate, but Tom missed 1...Bxe4 2. Rxe4, Qd3! and then f6 with Ng3 is just winning.
In the game White took with the pawn, and the game continued as Tom wrote - Bejtovic Jasmin

Bejtovic Jasmin 2307 -Oparin Grigory 2353
IM tournament, Olomouc 2009

The pattern is mate w/ bishop on f6 and rook on h-file. 
1.Nxf5 (1...exf5 2 Qxh7+ Kxh7 3.Rh4+ Bh6. 4.Rxh6+ Kxh6 5.Rh3#) 1...Bg7 2.Bxg7! (w/ same idea Qxh7+). Now if 2...gxh5 3.Bf6+ Kf8. 4.Nh6 with mate on g8. If 2...gxf5 you can again play 3.Qxh7+ Kxh7 4.Rh4+ Kg8 5.Rh8#. So that leaves 2...exf5 but i guess 3.Qxh7+ still works. 3...Kxh7 4.Bf6! Threatens mate... 4...g5 5.Rxg5. 1-0.

That is what Tom wrote, and it wins as well, but this is what I played in the game:

1. Qxh7+!, Kxh7
2. Rh4+, Bh6
3. Nxf5, Qc5+ (3...exf5 4. Rxh6+, Kxh6 5. Rh3# ; 3...gxf5 4. Rg7+, Kh8 5. Rxh6#)
4. Kh1, Qf8
5. Nxh6, g5
6. Rxg5  1-0

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